use new api in release-service

pull/1/head
Michael Jerger 11 months ago
parent 2fc59f105b
commit 88253f49ac

@ -1,18 +1,25 @@
from typing import List
from pathlib import Path
from ..infrastructure import GitApi, BuildFileRepository
from ..infrastructure import GitApi, ArtifactDeploymentApi, BuildFileRepository
from ..domain import Version, Release, ReleaseType
class ReleaseService:
def __init__(self, git_api: GitApi, build_file_repository: BuildFileRepository):
def __init__(
self,
git_api: GitApi,
build_file_repository: BuildFileRepository,
artifact_deployment_api: ArtifactDeploymentApi,
):
self.git_api = git_api
self.artifact_deployment_api = artifact_deployment_api
self.build_file_repository = build_file_repository
@classmethod
def prod(cls, base_dir: str):
return cls(
GitApi(),
ArtifactDeploymentApi(),
BuildFileRepository(base_dir),
)

@ -7,5 +7,6 @@ from .infrastructure import (
CredentialsApi,
GitApi,
TerraformApi,
ArtifactDeploymentApi,
)
from .repository import DevopsRepository, BuildFileRepository

@ -7,12 +7,13 @@ from src.main.python.ddadevops.domain import (
from src.test.python.domain.helper import (
BuildFileRepositoryMock,
GitApiMock,
ArtifactDeploymentApiMock,
build_devops,
)
from src.main.python.ddadevops.application import ReleaseService
def test_sould_update_release_type():
sut = ReleaseService(GitApiMock(), BuildFileRepositoryMock("build.py"))
sut = ReleaseService(GitApiMock(), ArtifactDeploymentApiMock(), BuildFileRepositoryMock("build.py"))
devops = build_devops({})
release = devops.mixins[MixinType.RELEASE]
sut.update_release_type(release, "MAJOR")

@ -150,3 +150,17 @@ class GitApiMock:
def checkout(self, branch: str):
pass
class ArtifactDeploymentApiMock:
def __init__(self):
pass
def post_release(self, target_url: str, tag: str, token: str):
pass
def post_asset(self, target_url: str, release_id: str, attachment: str, attachment_type: str, token: str):
pass
def calculate_checksums(self, build_path: str):
pass

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